21点游戏A计算方法

1.A既可以作为1，也可以作为11，计算所有牌面的总点数

2.算法逻辑：不管有多少个A,只把第一个A先计算成11，加起来，总和如果超过21点，把第一个A变成1

3.代码：

def count_points(foker_list):
    foker_list_tmp = []
    foker_list_len = len(foker_list)

    for i in foker_list:
        foker_list_tmp.append(i)

    for i in range(foker_list_len):
        if foker_list_tmp[i] in ('J','K','Q'):
            foker_list_tmp[i]=10

    for i in range(foker_list_len):
        if foker_list_tmp[i] == 'A':
            foker_list_tmp[i] = 11
            break
    for i in range(foker_list_len):
        if foker_list_tmp[i] == 'A':
            foker_list_tmp[i] = 1
    total=0
    for i in range(foker_list_len):
        total += int(foker_list_tmp[i])

    if total > 21:
        for i in range(foker_list_len):
            if foker_list_tmp[i] == 11:
                foker_list_tmp[i] = 1
    total=0
    for i in range(foker_list_len):
        total += int(foker_list_tmp[i])

    return total

foker_list = ['A', 'A', '5']
player_score3 = count_points(foker_list)
print(player_score3)
print(foker_list)

17
['A', 'A', '5']